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ZOJ Problem Set – 2417 Lowest Bit
, 2011年03月21日 , C Language , 评论 在〈ZOJ Problem Set – 2417 Lowest Bit〉中留言功能已關閉 ,

也是一道AC比較高的
感覺最近只對簡單題有feel?
盯著難題看了很久我只是想到了夜宵。。

Lowest Bit
Time Limit: 1 Second Memory Limit: 32768 KB

Given an positive integer A (1 <= A <= 100), output the lowest bit of A. For example, given A = 26, we can write A in binary form as 11010, so the lowest bit of A is 10, so the output should be 2. Another example goes like this: given A = 88, we can write A in binary form as 1011000, so the lowest bit of A is 1000, so the output should be 8.
Input

Each line of input contains only an integer A (1 <= A <= 100). A line containing "0" indicates the end of input, and this line is not a part of the input data. Output For each A in the input, output a line containing only its lowest bit.
Sample Input

26
88
0

Sample Output

2
8

我的代碼:

#include
main()
{
int i[100]={0},n,t=1,j,k,num=1;
while(scanf(“%d”,&n)!=EOF)
{
if(n==0) return 0;
while(n!=1)
{
i[t]=n%2;
n=n/2;
t++;
}
i[t]=1;
for(j=1;j<=t;j++)
{
if(i[j]==1)
{
for(k=1;k num=num*2;
break;
}
}
printf(“%d\n”,num);
t=1;num=1;
}
return 0;
}

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